Symmetric penetration, surface offset 0 mm Laying in the centre on a steel floor 200 x 200 x 4 mmįy vert = 6000N Fx horizontal = 6000 N on the blockįriction-coefficient = 1 stiffnes-factor = 1 Let us know if you have any other questions. This is different than some software that transmits the contact forces at the original locations of the parts regardless of how far they displace.) The normal contact force does not appear on the floor at the original location of the block. If the block moves 1 m to the right, the normal contact force should appear on the floor 1 m to the right of the original location.
Although linear stress is based on small displacement theory, the location of contact in linear stress does update based on the displacement. (I am not sure if you are performing linear stress or nonlinear stress. (The frictional stiffness described in the above article is one of those input.) If sliding occurs, some strange things can happen in the results such as the friction force going to 0, or the location of the normal force occurs somewhere else in the model that does not get reflected back to the supports. Even if the theoretical horizontal force is smaller than the theoretical friction force, there are other input that can allow the model to slide. Numerically, the horizontal force can be a fraction over the resistance force available from friction, and then the part will slide. The other possibility is that numerically the part has slid.If it has not converged, the results will not be correct. My guess is that you have 1 or more warnings that indicate the analysis did not converge.See the page Frictional stiffness for stick in Autodesk Nastran for some additional information about friction.
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